Math, asked by ashrita2, 1 year ago

Three consecutive integers such that when they are taken in increasing order and multiplied 2 3 and 4 respectively. They add up to 74 find these numbers.

Answers

Answered by aayusha52
17

Answer:

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Step-by-step explanation:

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Attachments:
Answered by XxxRAJxxX
0

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9

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