Three consecutive integers with a sum of negative 39
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Answered by
0
Answer:
Required three consecutive Integers are -12,-13 and -14
Step-by-step explanation:
Let x,(x+1) and (x+2) are three consecutive Integers.
/* According to the problem given,
Sum of three Integers = -39
=> x+x+1+x+2=-39
=> 3x+3=-39
/* Divide each term by 3, we get
=> x+1=-13
=> x = -13-1
=> x = -14
Therefore,.
Required three consecutive Integers are,
x = -14
x+1 = -14+1 = -13,
x+2 = -14+2 = -12
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Answered by
1
Let the three numbers be: x-1, x and x+1.
-Therefore, x-1 + x + x+1 =3x = 39
-Hence x, the middle number is 13.
-The other two numbers are 12 and 14.
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