Question

Three consecutive multiple of 7 adds upto 147 findi integers

Answer 1

Answer:

42 , 49, 56

Step-by-step explanation:

Let the multiples of 7 be 7a , 7(a+1) , 7(a-1) {since they are consecutive}

Now ,

7a + 7a + 7 + 7a - 7 = 147

21a = 147

a = 147/21 = 7

So, the multiples of 7 are (7×7) , (7×8) and 7×6) i.e. 49 , 56 42

Answer 2

Answer:

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