Three consecutive multiples of 11 are 363 find the multiples
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Let the 3 consecutive multiples of 11 be x, x+11, x+22.
Sum of these numbers= 363
=>x+(x+11)+(x+22)=363
=>x+x+11+x+22=363
=>3x+33=363
=>3x=363-33
=>3x=330
=>x=330/3
=>x=110
The multiples of 11 are:-
:.x=110
:.x+11=121
:.x+22=132
The three consecutive multiples of 11 whose sum is 363 are 110,121 & 132.
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