Question

Three consecutive multiples of 11 are 363 find the multiples

Answer 1

Answer:

Let the 3 consecutive multiples of 11 be x, x+11, x+22.

Sum of these numbers= 363

=>x+(x+11)+(x+22)=363

=>x+x+11+x+22=363

=>3x+33=363

=>3x=363-33

=>3x=330

=>x=330/3

=>x=110

The multiples of 11 are:-

:.x=110

:.x+11=121

:.x+22=132

The three consecutive multiples of 11 whose sum is 363 are 110,121 & 132.

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