Question

three consecutive multiples of 3 have a sum of 84

Answer 1

Hey there!!

Let the numbers be 3n , 3 ( n + 1 ) , 3 ( n + 2 )

If we add them, we get 84

3n + 3n + 3 + 3n + 6 = 84

9n + 9 = 84

9n = 75

( The sum cannot be 84) but can be 81

9n + 9 = 81

9 ( n + 1 ) = 81

n + 1 = 9

n = 8

Now, substitute,

Numbers are 24 , 27 , 30

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