Question

Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the square of the other two by 60 . find the numbers .​

Answer 1

Answer:

Since the middle number of the three consecutive numbers is x, the other two numbers are x -1 and x +1.

According to the given condition, we have

x² = [(x +1)² -(x -1)²] +60

x² = (x² +2x +1) -(x² -2x +1) +60 = 4x +60

x² -4x -60 = 0 => (x -10)(x +6) = 0

x = 10 or -6

Since x is a natural number, we get x = 10

Hence the three numbers are 9, 10, 11

Answer 2

Answer:

This is ur answer............