Question

three consecutive natural numbers are such that three times the middle number is greater than the sum of other two by 11, then the no.s are

15,16,17
9,10,11
10,11,12
11,12,13

Answer 1

Answer

10, 11 , 12

Step-by-step explanation:

Let the numbers be x

Therefore, x , x + 1 , x + 2

A/Q 3 ( x + 1 ) = x + x + 2 + 11

3x + 3 = 2x + 13

3x - 2x = 13 - 3

x = 10

Therefore, x + 1 = 11

x + 2 = 12