Three consecutive natural numbers are such that when they are taken in decreasing order and multiplied by 3, 4 and 5 respectively, they add up to 226. Find these numbers.
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If First number is x
Then second and third will be (x+1) and (x+2).
A.T.Q
3×(x+2)+4×(x+1)+5×(x)=226
(3x+6)+(4x+4)+(5x)=226
3x+6+4x+4+5x=226
3x+4x+5x+6+4=226
12x+10=226
12x=226-10
12x=216
x=216/12
x=8
*First number x = 8
*Second number (x+1) = (8+1) =9
*Third number (x+2) = (8+2)=10
Then second and third will be (x+1) and (x+2).
A.T.Q
3×(x+2)+4×(x+1)+5×(x)=226
(3x+6)+(4x+4)+(5x)=226
3x+6+4x+4+5x=226
3x+4x+5x+6+4=226
12x+10=226
12x=226-10
12x=216
x=216/12
x=8
*First number x = 8
*Second number (x+1) = (8+1) =9
*Third number (x+2) = (8+2)=10
StudyBuddy09:
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oh no
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the total sum is 110
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