Question

Three consecutive numbers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively the add up to 74. Find these numbers.

Answer 1

Answer:

(x)2+(x+1)3+(x+2)4=74

2x+3x+3+4x+8=74

9x+11=74

9x=74-11

x=63÷9

x=7

first number= x=7

second number= x+1=8

third number= x+2=9

Answer 2

Answer:

7, 8, 9

Step-By-Step Explanation:

Let the three consecutive integers are x, x+1 and x+2.

According to the question,

2x + 3(x+1) + 4(x+2) = 74

⇒ 2x + 3x +3 + 4x + 8 = 74

⇒ 9x + 11 = 74

⇒ 9x = 74 – 11

⇒ 9x = 63

⇒ x = 63/9

⇒ x = 7

Thus, the numbers are:

x = 7

x + 1 = 8

x + 2 = 9