Three consecutive numbers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively the add up to 74. Find these numbers.
Answers
Answered by
5
Answer:
(x)2+(x+1)3+(x+2)4=74
2x+3x+3+4x+8=74
9x+11=74
9x=74-11
x=63÷9
x=7
first number= x=7
second number= x+1=8
third number= x+2=9
Answered by
1
Answer:
7, 8, 9
Step-By-Step Explanation:
Let the three consecutive integers are x, x+1 and x+2.
According to the question,
2x + 3(x+1) + 4(x+2) = 74
⇒ 2x + 3x +3 + 4x + 8 = 74
⇒ 9x + 11 = 74
⇒ 9x = 74 – 11
⇒ 9x = 63
⇒ x = 63/9
⇒ x = 7
Thus, the numbers are:
x = 7
x + 1 = 8
x + 2 = 9
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