Three consecutive numbers have a sum of 6000 what could be the numbers
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Numbers are consecutive therefore let them be x, x+1, x+2
x+x+1+x+2=6000
3x+3=6000
3x=5997
x=1999
therefore numbers are 1999, 2000, 2001
:)
x+x+1+x+2=6000
3x+3=6000
3x=5997
x=1999
therefore numbers are 1999, 2000, 2001
:)
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