Three consecutive numbers have a sum of 66?
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Let the First consecutive no. = x
Second no. = x+1
Third no. = x+2
Sum = 66
x+x+1+x+2 = 66
3x +3 = 66
3x =66-3
3x =63
x = 63/3
x = 21
First no. = 21
Second no. = 21+1=22
Third no. = 21+2=23
Hope this may help you ....✌️
Second no. = x+1
Third no. = x+2
Sum = 66
x+x+1+x+2 = 66
3x +3 = 66
3x =66-3
3x =63
x = 63/3
x = 21
First no. = 21
Second no. = 21+1=22
Third no. = 21+2=23
Hope this may help you ....✌️
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