Question

Three consecutive numbers such that twice the first, 3 times the second, and 4 times the third together make 182.
The numbers in question are what ?​

Answer 1

Answer:

Let the smallest of three consecutive number or first consecutive number be x, thus other two numbers, means second and third consecutive numbers are x + 1 and x + 2 respectively

Now, twice the first, 3 times the second and 4 times the third together make 182.

Twice the first is 2x, 3 times the second is 3 (x +1) and 4 times of third 4 (x + 2)

2x + 3 ( x + 1) + 4 (x + 2) = 182

2x + 3x + 3 + 4x + 8 = 182

9x + 11 = 182

9x = 182 - 11 = 171

9x = 171

x = 171/9

x = 19

The smallest of three consecutive number is 19

The second consecutive number is x + 1 = 19 + 1 = 20

The third consecutive number is x + 2 = 19 + 2 = 21

This three consecutive numbers are 18, 20 and 21

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