Question

three consecutive numbers that add up to 246.

Answer 1

Answer:

Therefore, three consecutive integers that add up to 246 are 81, 82, and 83.

Answer 2

Answer:

81, 82, 83

Step-by-step explanation:

Let the first number be x

then,

the three numbers are: x, (x+1),(x+2)

A.T.Q

x+(x+1)+(x+2) = 246

x+(x+1)+(x+2) = 2463x + 3 = 246

x+(x+1)+(x+2) = 2463x + 3 = 2463(x+1) = 246

x+(x+1)+(x+2) = 2463x + 3 = 2463(x+1) = 246 (x+1)= 82

x+(x+1)+(x+2) = 2463x + 3 = 2463(x+1) = 246 (x+1)= 82 x= 81

The three numbers are: x = 81

x = 81 (x+1) = 82

x = 81 (x+1) = 82 (x+2) = 83

Hope it helps...

It was pleasure answering you...