three consecutive odd integers add up to 93,find the numbers. pls answer step by step
Answers
Answered by
2
Answer:
The integers are 29, 31 and 33
Step-by-step explanation:
let the first integer be 'x'
the next odd integer will be 'x + 2'
and then the next integer will be 'x + 4'
It is given sum of these numbers is 93 ....So
x + x + 2 + x + 4 = 93
3x + 6 = 93
3x = 87
x = 87 ÷ 3
x = 29
Hence the integers will be 29, 29 + 2 = 31 and 29 + 4 = 33.
Hope this helps....
Answered by
1
Solution:
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
x + (x + 2) + (x + 4) = 93
x + x + 2 + x + 4 = 93
3x + 6 = 93
3x = 93 - 6
3x = 87
x = 87/3
x = 29 = first odd integer
x + 2 = 29 + 2 = 31 = second odd integer
x + 4 = 29 + 4 = 33 = third odd integer
Therefore, 29, 31, 33 are the three consecutive odd integers which add up to 93.
Hope this will be helpful
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
x + (x + 2) + (x + 4) = 93
x + x + 2 + x + 4 = 93
3x + 6 = 93
3x = 93 - 6
3x = 87
x = 87/3
x = 29 = first odd integer
x + 2 = 29 + 2 = 31 = second odd integer
x + 4 = 29 + 4 = 33 = third odd integer
Therefore, 29, 31, 33 are the three consecutive odd integers which add up to 93.
Hope this will be helpful
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