Question

three consecutive odd integers are such that if the largest is subtracted from twice their sum, the result is 93 ,then the smallest odd integer is​

Answer 1

Step-by-step explanation:

you can see my attachment

Answer 2

Answer:

The three integers are 45, 46, 47.

Step-by-step explanation:

Let the:

1st integer     = x

2nd integer   = x + 1

3rd integer    = x + 2

 

• Now using these variables, we can write an equation based on the description.  

       [x + 2(x + 2)] - [x - 1] = 93

This equation is saying that the sum of two numbers and another number has a difference of 93. The positive difference suggests that the sum of the two numbers is the larger value.  

Now we solve for x:

• Distribute to get rid of parentheses.  

       x + 2x + 4 - x - 1 = 93  

      2x + 3 = 93

• Subtract 3 on both sides of the equation.  

        2x = 90    

• Divide both sides of the equation by 2.  

        x = 45    

• Finally, substitute this value of x into the variables to get your integers.

I hope I have given you the answer you were looking for.

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HAPPY LEARNING!