Math, asked by Anonymous, 7 months ago

three consecutive odd integers are such that if the largest is subtracted from twice their sum,the result is 93,then the smallest integer is
(i)17 (ii)18 (iii)19 (iv)20
please write in simple language I am in 7 grade​​

Answers

Answered by samikshabhatia20
2

Step-by-step explanation:

let the integers be x,x+2,x+4

according to the question,

2(x+x+2+x+4) - (x+4)=93

2(3x+6)-x-4=93

6x+12-x-4=93

5x+8=93

5x=85

x=85/5

x=17

answer=(i)17

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