three consecutive odd integers are such that if the largest is subtracted from twice their sum,the result is 93,then the smallest integer is
(i)17 (ii)18 (iii)19 (iv)20
please write in simple language I am in 7 grade
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Step-by-step explanation:
let the integers be x,x+2,x+4
according to the question,
2(x+x+2+x+4) - (x+4)=93
2(3x+6)-x-4=93
6x+12-x-4=93
5x+8=93
5x=85
x=85/5
x=17
answer=(i)17
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