Question

Three consecutive odd integers have a sum of 33 . Find the integers.

Answer 1

$(2x +1) + (2x + 3) + (2x + 5) = 33 \\ 6x + 9= 33 \\ 6x = 24 \\ x = 4$

Therefore numbers are 9, 11 and 13.

Answer 2

let the integers be -

n, n+2, n+4

given, sum =33

so, n+n+2+n+4=33

so, 3n+6=33

3n=27

n=9

therefore, integers are-

9, 11, 13

please mark my answer brainliest.