Question

Three consecutive odd integers such that the second is 20 less than 3 times the third integer.

Answer 1

Answer:

Let the integer be x, x+2, and x+4.

So,

x+2 = 3(x+4)+20

x+2 = 3x+12+20

x-3x = 12+20-2

2x = 30

x = 15

So, the consecutive odd interger are 15, 17 and 19.