Question

Three consecutive odd natural numbers are such that the product of the first and second number is 1 more than two times the third number. Which is the second number

Answer 1

Answer:

5

Step-by-step explanation:

consider the odd natural numbers as,

first odd natural number= n

second odd natural number= n+2

third. odd natural number= n+4

fourth odd natural number = n+6

product of the first and second number =

n×(n+2)

two times the third number = 2 ( n+4 )

n(n+2) = 1+ 2 ( n+4 )

${n}^{2} + 2n = 1 + 2n + 8 \\ {n}^{2} + 2n = 2n + 9$

cancel the 2n in both the sides....

${n}^{2} = 9 \\ n = \sqrt{9 } = 3$

if n = 3

then the second odd natural number= n+2 = 3+2 =5