Question

three consecutive odd natural numbers are such that the product of the first and third is greater than 4 times the middle by 1 find the numbers​

Answer 1

Let three consecutive odd natural numbers be M, M + 2, M + 4.

Product of first and third number is greater than four times the middle one by one.

We have..

First number = M

Second number = M + 2

Third number = M + 4

According to question,

=> M(M + 4) = 4(M + 2) + 1

=> M² + 4M = 4M + 8 + 1

=> M² + 4M = 4M + 9

=> M² + 4M - 4M = 9

=> M² = 9

=> M = $\pm$3

=> M = +3

(-3 neglected)

So,

First number = M

=> 3

Second number = M + 2

=> 3 + 2

=> 5

Third number = M + 4

=> 3 + 4

=> 7

∴ Numbers are 3, 5 and 7.

Answer 2

Answer:

here your answer...........

Step-by-step explanation:

let the three consecutive odd natural

numbers be a, a+2, a+4.

According to question

the product of the first and third is greater than 4 times the middle by 1

then

a(a+4)=4(a+2)+1

a^2+4a=4a+8+1

a^2=9

a=3 and -3 (negative signs neglected)

a=3

therefore the numbers are,

a=3

a+2=3+2=5

a+4=3+4=7