Question

Three consecutive odd natural numbers are such that the product of first and third isGreater than four times the middle by 1 what are the numbers

Answer 1

Answer:

let 1st odd number be x,second x+2 and third x+4

\begin{lgathered}x(x + 4) =4(x + 2) + 1 \\ {x}^{2} + 4x = 4x + 8 + 1 \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3 \: and \: x = - 3(neglect \: this) \\ the \: numbers \: are \: 3 \\ 5 \\ and \: \: \: \: 7\end{lgathered}

x(x+4)=4(x+2)+1

x

2

+4x=4x+8+1

x

2

=9

x=

9

x=3andx=−3(neglectthis)

thenumbersare3

5

and7