Question

three consecutive odd natural numbers are such that the product of the first and third is a greater than 4 times the middle by 1 find the numbers

Answer 1

let 1st odd number be x,second x+2 and third x+4
$x(x + 4) =4(x + 2) + 1 \\ {x}^{2} + 4x = 4x + 8 + 1 \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3 \: and \: x = - 3(neglect \: this) \\ the \: numbers \: are \: 3 \\ 5 \\ and \: \: \: \: 7$