Three consecutive odd natural numbers are such that the product of the first and third is greater than four times the middle by 1 find the numbers
Answers
Answered by
4
Answer:
Three consecutive odd natural numbers are such that the product of the first and third exceeds four times the middle by 1 , then the numbers are 3, 5 and 7 .
Answered by
1
Answer:
let 1st odd number be x,second x+2 and third x+4 x(x + 4) = 4(x + 2) + 1 x² + 4x 4x + 8 + 1 = 2 x² = 9 X = 3 and x = -3(neglect this) x = √9 the numbers are 3 5 and 7
Similar questions