Question

Three consecutive odd number whose is 147

Answer 1

Answer:

47,49,51

Step-by-step explanation:

let the 3 consecutive no. be x , x+2 , x+4

A.T.Q

x + (x+2) + (x+4) = 147

= 3x + 6 = 147

= 3x = 147 - 6

= 3x = 141

= x = 47

the three consecutive no. is 47 , 49 , 51

Answer 2

Given:

Find three consecutive odd numbers whose sum is 147.

To find:

Three consecutive odd numbers.

Solution :

Let 3 consecutive odd nos

x+1, x+3, x+5.

According to the given question:

=> x+1, x+3, x+5=147

=> 3x+9=147

=> 3x=147-9

=> 3x = 138

=> x = 138/3

=> x = 46  

The three consecutive odd numbers are :

=>  x+1 = 46+1=47

=> x+3 = 46+3=49

=> x=5 = 46+5=51