Question

Three consecutive odd number whose is 147​

Answer 1

Let first number be x.

Second and third numbers are : x + 2 , x + 4

x, x+2, x+4

x + x + 2 + x + 4= 147

3x + 6 = 147

x = 141/3

x = 47

Numbers are: 47, 49 and 51.

Answer 2

Answer:

Answer=> 47, 49, 51

Hope That Helps ☺️

Mark That PARCHO As Brainlist ✨