Question

Three consecutive odd numbers whose sum is 987

Answer 1

Answer:

327,329,331

Step-by-step explanation:

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Answer 2

Answer:327 + 329 + 331 = 987.

Step-by-step explanation:Let us assume that, three consecutive odd numbers are 2n-1, 2n+1 and 2n+3

Given 2n-1+2n+1+2n+3 = 987

6n + 3 = 987

6n = 987 – 3

6n = 984

n = 164

Therefore, the three consecutive no’s are (2*164) – 1 = 327, (2*164) + 1 = 329, and (2*164) + 3 = 331.

Sum of these three numbers = 327 + 329 + 331 = 987.

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