Question

Three consecutive positive even numbers are such that thrice that first number exceeds double the third by 2 the third number is?

Answer 1

It is said that three positive even integer therefore the difference between the integers are 2.

Let the integers be x, x+2, x+4.

According to question:-
3(x) -2 = 2(x+4)
3x -2 = 2x+8
3x-2x = 8+2
x = 10

So the numbers are
x = 10
x+2 = 10+2
= 12
&
x +4 = 10+4
= 14.

Answer 2

Answer:

The third number is 14.

Step-by-step explanation:

Let's assume that the three consecutive positive even numbers be x, x+2, x+4.

According to the question, the equation will be,

⇒ 3x - 2 = 2(x + 4)

⇒ 3x - 2 = 2x + 8

⇒ 3x - 2x = 8 + 2

⇒ x = 10

Therefore, the consecutive positive even numbers are as follows:

x = 10

x + 2 = 12

x + 4 = 14

Hence, the third even number is 14.

To know more about algebra, click on the link below:

https://brainly.in/question/17865936

To know more about positive even numbers, click on the link below:

https://brainly.in/question/10853627

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