Question

Three consecutive positive integers are such that the sum of square of second integer and the
product of first and third integer is 49. Find the integers.​

Answer 1

let the consecutive positive integers be,

x, x+1, x+2

Given-

Sum of :

Sq. of 2nd integer= (x+1)²

Product of 1st and 3rd integers= (x)(x+2)

Total sum = 49

Find-

The actual integers.

Solution-

(x+1)² + x(x+2)=49

(x²+2x+1) +x²+2x = 49

x²+2x+1 +x²+2x = 49

2x²+4x+1 = 49

2x²+4x = 49-1 [by transposition]

2x²+4x = 48

2x²+x = 48/4

2x²+x = 12

x²+x = 12/2

x²+x = 6

x+x = √6

2x = √3×2

x = √3×2 =√3

2

x = √3

Hope it helps!

Answer 2

Answer:

MARK AS BRAINLIEST ANSWER

Explanation: