Question

three consecutive positive integers are such that the sum of the square of the first and the product of the other two is 46 find the integers

Answer 1

plzzzz mark it as brainlist...plzzz..

Answer 2

Assume 3 positive integers p, p + 1 and p + 2

★Situation

p² + (p + 1)(p + 2) = 46

2p² + 3p + 2 - 46 = 0

2p² + 3p - 44 = 0

2p² - 8p + 11p - 44 = 0

2p(p - 4) + 11(p - 4) = 0

(2p + 11)(p - 4) = 0

p = 4

★Therefore integers are 4,5 and 6