Question

Three consecutive positive integers such that the sum of the square of the first and the product of the other two is 46 find the integers.​

Answer 1

Answer:

Let the integers be = x , x+1 , x+2

According to question

(x)² + (x+1)(x+2) = 46

x² + x² + 3x + 2 = 46

2x² + 3x = 46 - 2

2x² + 3x - 44 = 0

2x²+11x - 8x - 44 = 0

x( 2x + 11 ) -4 ( 2x + 11 )

(x - 4) ( 2x + 11 )

So, x = 4 , x = -11/ 2

Since the value can't be negative, x = 4

So , three consecutive integers are = 4, 5 ,6

Step-by-step explanation:

Please mark me as brainliest and vote !!!