Question

three consecutive producer of 600 10 are​

Answer 1

Answer:

see the answer

Explanation:

Let x = the first of the three consecutive numbers.

Let x+1 = the second of the three consecutive numbers.

Let x+2 = the third of the three consecutive numbers.

x+(x+1)+(x+2)=600 Given

3x+3=600 Addition

3x=597 Subtract 3 from both sides

x=199 Divide both sides by 3

x+1=200 Addition

x+2=201 Addition

Check:

x+(x+1)+(x+2)=600 Given

199+200+201?=600 Substitution

600=600 Addition

QED

Answer: 199, 200, and 201 are the three consecutive numbers

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