Question

Three consecutive terms of an A.P. are respectively 3t-1,3t+5 and 5t+1.Find t.

Answer 1

Answer:

Step-by-step explanation:

T2-t1= t3-t2

3t+5-3t+1=5t+1-3t-5

6=2t-5

11=2t

11/2=t

Now

1st=3t-1

3×11/2-1

33/2-1

33-2/2

31/2

Put the value if t in 2th and 3rd eq u will get the ans

Hope it helps u..

Answer 2

3t-1,3t+5and5t+1are in a.p
therefore,
a=3t-1
b=3t+5
c=5t+1
now,we know that b=a+c/2
3t+5=3t-1+5t+1
...................
2
2(3t+5)=3t-1+5t+1
6t+10=8t-0
10=8t-6t
10=2t
10/2=t
5=t