three consecutive terms of an arithametic sequence are 3,x and -5.what is x
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X+3 3 X--1 7X--2 are 3 terms of Arithmateci Swquence (AP)
Common difference =3X-1 -X—3 =2X -4
2) 7X--2-3X+1 =4X--1
They are equal being common diffrence
4X-1=2X -4
2X = —3
X= — 3/2
First term =X+3 = --3/2+2 = (--3+4) /2 = -1/2
-1/2 -11/2 -25/2 ------2--b
Sum of n terms of AP = n/2 [ 2a +(n-1) d]
a= -- 1/2 d= -3/2
Sn= n/2 [ --1 +(n-1) (--3/2)]
Extension of the problem( For students of 10th to 12th )
Find sum of 10 terms
S10 = 10/2 [ --1 +9 (-3/2)]
=5 (-29/2)
=-- 145 /2 = — 72.5
S10 = --72.5
Step-by-step explanation:
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