three consecutive vertices of a parallelogram ABCD are A(1,2);B(1,0) and C(4,0). the co-ordinates of the forth vertex Dare:
please help !!!!!!!!
Answers
Answer:
Step-by-step explanation:
we have given three sides of parallogram A(1,2) b(1,0) c(4,0) and we know that
sides of parallogram biset at mid point x +1/2 = 5 and y+0/2 = 2 so here we calculate this x = 4 and y = 1 so the forth cordinate of is (4,1)
Answer:
(4,2)
Step-by-step explanation:
Let M be the midpoint of the diagonals of the parallelograms ABCD.
Co-ordinate of M will be the midpoint of diagonal AC.
Given points are A(1,2),B(1,0) and C(4,0)
Consider line AC
x1= 1, y1
= 2
x2= 4, y2= 0
By midpoint formula, x=(x1
+x2)/2
∴x=(1+4)/2=5/2
By midpoint formula, y=(y1
+y2
)/2
∴y=(2+0)/2=2/2=1
Hence the co-ordinates of M are (5/2,1).
M is also the midline of diagonal BD.
Consider line BD and M as midpoint.
x1
= 1, y1
= 0
x=5/2,y=1
By midpoint formula, x=(x1
+x2
)/2
∴5/2=(1+x2
)/2
∴5=1+x2
∴x2
=5−1=4
By midpoint formula, y=(y1
+y
2
)/2
∴1=(0+y2
)/2
∴1=y2
/2
⇒y2
=2
Hence the co-ordinate of D are (4,2).
Hope it will be helpful :)