Question

Three consecutive whole numbers add up to 144. If the lowest number is n,
a Write down an expression for the other two numbers in terms of n.
b Write down an equation involving n.
c Find n then write down the three consecutive whole numbers

Answer 1

a. n+1,n+2

a. n+1,n+2b. n+n+1+n+2=144

a. n+1,n+2b. n+n+1+n+2=144c. n+n+1+n+2=144

a. n+1,n+2b. n+n+1+n+2=144c. n+n+1+n+2=144 3n+3=144

a. n+1,n+2b. n+n+1+n+2=144c. n+n+1+n+2=144 3n+3=144 3n=144-3

a. n+1,n+2b. n+n+1+n+2=144c. n+n+1+n+2=144 3n+3=144 3n=144-3 3n=141

a. n+1,n+2b. n+n+1+n+2=144c. n+n+1+n+2=144 3n+3=144 3n=144-3 3n=141 n=141/3

=47

n+1=48

n+2=49

Explanation:

Let us take an example : sum as 16

then,first we will figure out the consecutive numbers

if lowest number is n then others are n+1,n+2

Solve it by transposition method