Three constant forces F1=2i-3j+2k F2=i+j+I and F3=3i+j-2k displace a particle from (1,-1,2) to(-1,-1,3) and then to (2,2,0) then work done is
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Explanation:
Fr = (6,-1,1)
diS. d= (1,3,-2)
so, W= Fr dot d = 6-3-2 = 1 joule
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