Math, asked by meme193, 3 months ago

Three containers have their volumes in the ratio 3: 4: 5. They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of (4 : 1), (3 : 1) and (5:2) respectively. The ratio of milk and water in the fourth container contains all the above three mixtures is
(1) 4 : 1
(2) 151 : 48
(3) 157 : 53
(4) 5 : 2​

Answers

Answered by XFD10487
1

Answer:

(3) 157:53

Step-by-step explanation:

Let the volumes be 3x,4x,5x respectively.

Container with volume 3x:

Milk = 4/(4+1)*3x

Water = 1/(4+1)*3x

Container with volume 4x:

Milk = 3/(3+1)*4x

Water = 1/(3+1)*4x

Container with volume 5x:

Milk = 5/(5+2)*5x

Water = 2/(5+2)*5x

Total milk = 12/5x+12/4x+25/7x = 140/1256x

Total water = 3/5x+4/4x+10/7x = 424/140x

Ratio of milk to water in 4th container = 1256/424=157:53

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