Math, asked by rodrigueseliza7349, 11 months ago

Three containers have volumes in the ratio 3 :4 : 5. They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of 4 : 1, 3:1 and 5 :2 respectively. The contents of all these three containers are poured into a fourth container. The ratio of milk and water in the fourth container is:

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Answered by sprao534
22
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Answered by VineetaGara
5

The ratio of milk and water would be 157:53

1) The ratio of volume of containers is 3:4:5

Let the volume of containers be 3x,4x,5x

2) For the first container, ratio of milk and water is 4:1

Therefore Milk in first container would be 3x *(4/5) = 12x/5

And water in first container would be 3x*(1/5) = 3x/5

3) For the second container, ratio of milk and water is 3:1

Therefore Milk in second container would be 4x *(3/4) = 3x

And water in second container would be 4x*(1/4) = x

4)  For the third container, ratio of milk and water is 5:2

Therefore Milk in third container would be 5x *(5/7) = 25x/7

And water in third container would be 5x*(2/7) = 10x/7

5) Total amount of milk would be : 12x/5 + 3x + 25x/7 = 314x/35

Total amount of water would be : Total volume - total milk =  12x - 314x/35 = 106x/35

6) ratio of milk and water would be 314x:106x = 157:53

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