Three copper cube whose edges measures scm×4cm×3cm respectively are meter to form signal cube. Find the surface are of New cube
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volume of new cube=(volume of 1st cube+volume of 2nd cube+volume of 3rd cube)
a^3 =[(a1)^3+(a2)^3+(a3)^3]
a^3 = (5/100)^3+(4/100)^3+(3/100)^3
a^3=125/1000000+64/1000000+27/1000000
a^3=(125+64+27)/1000000
a^3=216/1000000
a^3=(2×3)^3
a=6m
total surface area of new cube=6a^2
=6×(6)^2
=(6×36)m^2
=216m^2
a^3 =[(a1)^3+(a2)^3+(a3)^3]
a^3 = (5/100)^3+(4/100)^3+(3/100)^3
a^3=125/1000000+64/1000000+27/1000000
a^3=(125+64+27)/1000000
a^3=216/1000000
a^3=(2×3)^3
a=6m
total surface area of new cube=6a^2
=6×(6)^2
=(6×36)m^2
=216m^2
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