Three couples (husbands and their wives) must sit at a round table in such a way that no husband is placed next to his wife. How many configurations exist?. If seats are occupied at random, what is the probability of such a configuration?
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So the number of ways in which they can swap their seats are (2!) ^3 =2*2*2=8. Hence the total number of arrangements are : 6*8=48. Hence, the answer is 48.....................
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Answer:
So the number of ways in which they can swap their seats are (2!) ^3 =2*2*2=8. Hence the total number of arrangements are : 6*8=48. Hence, the answer is 48.....................
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