Three cows owned by three farmers are tied at three corners of a triangular plot with ropes of 7m length each. Find the area grazed by cows. What value is depicted by the farmers?
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Let the angles of the triangle be a,b & c ;
Area grazed by the cow
= area of a sector
= (∅/360)×πr²
1. Area grazed by 1st cow
= (a/360)×π×7²
= (a/360) × 22×7
= 77a/180
2. Area grazed by 2nd cow
= (b/360)×(22/7)×7²
= 77b/180
3. Area grazed by 3rd cow
= (c/360)×(22/7)×7²
= 77c/180
•Total area grazed by the cows
= (77a/180)+(77b/180)+(77c/180)
= (77/180) (a+b+c)
= (77/180)×(180)
-------(a+b+c=180° -> angle sum property of a triangle)
= 77 m²
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Area grazed by the cow
= area of a sector
= (∅/360)×πr²
1. Area grazed by 1st cow
= (a/360)×π×7²
= (a/360) × 22×7
= 77a/180
2. Area grazed by 2nd cow
= (b/360)×(22/7)×7²
= 77b/180
3. Area grazed by 3rd cow
= (c/360)×(22/7)×7²
= 77c/180
•Total area grazed by the cows
= (77a/180)+(77b/180)+(77c/180)
= (77/180) (a+b+c)
= (77/180)×(180)
-------(a+b+c=180° -> angle sum property of a triangle)
= 77 m²
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