Question

three cube each of volume is 216m3 joined end to end find the surface area of the resulting solids​

Answer 1

Answer ⤵️

$<b>Heya mate. (^_-). Solution below.$✓✓

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♥ Volume of 1 cube = 216 cm³

But, volume of cube = a³(a = edge)

=> a³ = 216

=> a = ³√216

=> a = 6 cm

•°• Edge of one cube = 6 cm

♥ Now, three cubes are joined end to end.

Then, dimensions of resulting cuboid,

length = 6 + 6 + 6 = 18 cm

breadth = 6 cm

height = 6 cm

♥ Then, Total surface area of the cuboid,

= 2(lb + bh + hl)

= 2 [(18 × 6) + (6 × 6) + (6 × 18)]

= 2 [108 + 36 + 108]

= 2(252)

= 504 cm²

•°• T.S.A of the resulting cuboid = 504 cm².

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Thank you.. ^_^