three cube each of volume is 216m3 joined end to end find the surface area of the resulting solids
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♥ Volume of 1 cube = 216 cm³
But, volume of cube = a³(a = edge)
=> a³ = 216
=> a = ³√216
=> a = 6 cm
•°• Edge of one cube = 6 cm
♥ Now, three cubes are joined end to end.
Then, dimensions of resulting cuboid,
length = 6 + 6 + 6 = 18 cm
breadth = 6 cm
height = 6 cm
♥ Then, Total surface area of the cuboid,
= 2(lb + bh + hl)
= 2 [(18 × 6) + (6 × 6) + (6 × 18)]
= 2 [108 + 36 + 108]
= 2(252)
= 504 cm²
•°• T.S.A of the resulting cuboid = 504 cm².
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Thank you.. ^_^
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