Question

THREE CUBES EACH OF EDGE 4M ARE JOINED END TO END.FIND THE SURFACE AREA OF THE RESULTING CUBOID.

Answer 1

Answer:

Step-by-step explanation:

Edge of cube = side of cube = 4m

Lenght of cuboid = 4 +4 +4 = 12 m

Breadth of cuboid = 4m

Hieght of cuboid = 4m

Surface area of remaining cuboid = Total surface Area of cuboid

2 ( lb +bh+hl)

2 ( 12×4 +4×4+4×12)

2( 48+16+48)

2(112)

224

•:• THE SURFACE AREA OF RESULTING CIBOID IS 224 CM ^2

Answer 2

The cubes are joined end to end

Length of the cuboid = (4+4+4)m = 12m

Breadth of the cuboid = 4m

Height of the cuboid = 4m

Surface area of the cuboid = 2(lb+bh+lh)

= 2×(12×4+4×4+12×4)

=224 m cube