Three cubes each of side 5 cm are joined to the end. find the surface area of the resultant cuboid.
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hiii!!!
here's ur answer...
given the side of the cube = 5cm
ATQ,
three cubes of side 5cm are joined,
hence, m it will form a cuboid.
therefore length of the cuboid = 5 + 5 + 5
= 15cm
breadth of the cuboid = 5cm
height of the cuboid = 5cm
TSA (Surface area) of the cuboid = 2(lb + bh + lh)
= 2 [ ( 15 × 5 ) + ( 5 × 5 ) + ( 15 × 5 ) ]
= 2 ( 75 + 25 + 75 )
= 2 × 175
= 350cm²
hope this helps..!!
here's ur answer...
given the side of the cube = 5cm
ATQ,
three cubes of side 5cm are joined,
hence, m it will form a cuboid.
therefore length of the cuboid = 5 + 5 + 5
= 15cm
breadth of the cuboid = 5cm
height of the cuboid = 5cm
TSA (Surface area) of the cuboid = 2(lb + bh + lh)
= 2 [ ( 15 × 5 ) + ( 5 × 5 ) + ( 15 × 5 ) ]
= 2 ( 75 + 25 + 75 )
= 2 × 175
= 350cm²
hope this helps..!!
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