Three cubes each of side 5cm are joined end to end. Find the surface area of the resulting solid
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resulting solid is a cuboid
therefore l×b×h=15×5×5
tsa of cuboid= 2(lb+bh+hl)
2(15×5+5×5+5×15)
2(75+25+75)
2×175=350
therefore l×b×h=15×5×5
tsa of cuboid= 2(lb+bh+hl)
2(15×5+5×5+5×15)
2(75+25+75)
2×175=350
mehtani04karanp137z4:
but the answer is 350 i know the answer but i don't know how to solve it
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SOLUTION :
Given :
each side of three similar cube edge is 5cm.
According to the question,
Three cubes are joined end to end
So,
The new resulting solid will be a cuboid
So,
Its new dimensions will be
length (l) = 5+5+5 = 15 cm
breadth (b) = 5 cm
height (h) = 5 cm
Now,
To be found
the Total Surface Area of the cuboid (new solid)
As we know,
The TSA of cuboid is 2(lb + bh +hl) units
= 2(15 × 5 + 5 × 5 + 5 × 15)
= 2(75 + 25 + 75)
= 2(175)
= 350
Hence,
∴ The Total Surface Area of the new solid (cuboid) is 350 cm.
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