Three cubes each of side 5cmare joined end to end.Find the surface area of new cuboid.
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Answered by
1
Length of each side of cube = 5 cm
Now, 3 cubes are joined end to end.
So, the length of the resulting cuboid will be = 5+5+5 = 15 cm
But, the breadth and height will remain the same.
So, Breadth = 5 cm and Height = 5 cm
Surface area of the cuboid = 2(LB + BH +HL)
= 2(15*5 + 5*5 + 5*15)
= 2(75 + 25 + 75)
= 2*175
Surface area of the cuboid = 350 sq cm
I hope it is helped you
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Now, 3 cubes are joined end to end.
So, the length of the resulting cuboid will be = 5+5+5 = 15 cm
But, the breadth and height will remain the same.
So, Breadth = 5 cm and Height = 5 cm
Surface area of the cuboid = 2(LB + BH +HL)
= 2(15*5 + 5*5 + 5*15)
= 2(75 + 25 + 75)
= 2*175
Surface area of the cuboid = 350 sq cm
I hope it is helped you
follow me
Answered by
6
Length=15
Breath=5
Hight=5
S.A of cuboid =2(15×5+5×5+15×5)cm^2
=2(75+25+75)cm^2=350cm^2
Breath=5
Hight=5
S.A of cuboid =2(15×5+5×5+15×5)cm^2
=2(75+25+75)cm^2=350cm^2
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