Three cubes each of side 6 cm are joined together side by side to form a cuboid. (a) Find the surface area of the resultant cuboid. (b) Is this surface area equal to the sum of the surface areas of the three separate cubes?
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Answer:
TSA=1056sqcm
Step-by-step explanation:
When three cubes of side 6cm are joined to form a cuboid
length of cuboid is 6cm
breadth=6cm*3=18cm
and height=6cm
TSA=2(lh+bh+lb
TSA=2(6*6+18*6+18*6)
TSA=2(36+108+108)
TSA=2(252)
TSA=504sqcm
B.TSA OF ONE CUBE OF SIDE 6CM=6*6*6
=216CM^2
TSA OF SUCH THREE CUBES=216SQCM+216SQCM+216SQCM
TSA=648CM
IE the sum of the surface areas of the three separate cubes is not equal to the TSA of the newly formed cuboid
hence proved
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