Question

Three cubes each of the volume 64 cm cube are joining end to end the surface area of the resulting cuboid is ?​

Answer 1

༒ Qυєѕтiσи ༒

╔════════◄••❀••►════════╗

Three cubes each of the volume 64 cm cube are joining end to end the surface area of the resulting cuboid is ?

╚════════◄••❀••►════════╝

★彡 Sσℓυтiσи 彡★

✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏

We know that

Volume of both cubes is 64cm³

⛬ One side = (64)^ ⅓

= 4

The cubes are joined end to end (Given)

• Length = 8 cm
• Breadth = 4 cm
• Height = 4 cm

Surface area of resulting cuboid :-

⟹ 2 ( lb + bh + hl )

⟹ 2 ( 32 + 16 + 32 )

⟹ ( 2 × 80 ) cm²

⟹ 160 cm²

⛬ Surface area of resulting cuboid is 160 cm²

Answer 2

Volume of each cube=64cm³

(Sides)³=64cm³

(sides)³=(4cm)³

sides=4cm

Therefore, dimensions of cuboid= 4cm × 4cm × 12cm

Surface area of cuboid= 2(lb+lh+bh)

=> 2(4cm×4cm+4cm×12cm+12cm×4cm)

=> 224cm²

Hope it helps you ☺️,

Please mark me as brainlist .