Three cubes each of volume 216 cubic cm are joined end to end. Find the surface area of
the resulting cuboid.
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Answer:
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volume of 3 cube = 216
a^3= 216
a= 3√ 216
a= 6 cm
then
leght of cubiod =6x3= 18 cm
height of cubiod= 6cm
breadth cubiod = 6 cm
Then,
total surface area of cubiod= 2(lb+bh+hl)
= 2(18x6 + 6x6 +6x18)
= 2( 108 + 36 + 108)
= 2x 252
= 504 cm^2
Step-by-step explanation:
hence , the surface are of cubiod is 504 cm^2
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