Question

Three cubes each of volume 216 m3 are  joined end-to-end.  Then, what is the surface area of the resulting solid?

Answer 1

Cube volume 216 m3 so its every edge is 6m

since three cubes of volume 216 m3 are joined together so we get the cuboid of length

=(6+6+6)=18m

Breadth of the resulting cuboid is 18m
Height of the resulting cuboid is 18m

surface area of the resulting solid or cuboid is

=2(lb + bh + lh)
=2{(18 x 6) + (6 x 6) + (6 X 18)}
=2 {108+36+108}
=2 X 252
=504m^2


surface area of the resulting solid is 504m^2

Answer 2

Given :

• Three cubes each of volume 216 m³ are joined end-to-end.  

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Find :

• What is the surface area of the resulting solid?

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Formula :

★ TSA = 2 (Ib + bh + hl).

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Concept :

• Using this "Total surface area" formula we can easily solve this equation.

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• In the question there following terms are important:

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1. Length (L) = 6³ = 18 cm.
2. Breadth (B) = 6 cm.
3. Height (H) = 6 cm.
4. 216³ = 3√216
5. 3√216 = 6 cm

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Calculations :

→ 2 (18 × 6 + 6² + 18 × 6)²

→ 2 (108 + 36 + 108)²

→ 504 cm²

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Therefore, 504 cm² is the total surface area of resulting solid.